r = ( 5 − 2 K) i + ( 1 + 3 K) j + ( 6 − 5 K) k. In cartesian form: 5 − x 2 = y − 1 3 = 6 − z 5. If I take a = 3 i + 4 j + 1 k and b = 5 i + 1 j + 6 k. I get: b − a = 2 i − 3 j + 5 k. r = 3 i + 4 j + 1 k + K ( 2 i − 3 j + 5 k) r

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