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x ( z) = c 2 J 0 ( i z) + c 3 Y 0 ( − i z) + c 1 x p ( z) The general solution of Eq. ( 1) is on the form : x ( t) = c 2 J 0 ( i e t) + c 3 Y 0 ( − i e t) + c 1 x p ( e t) x p ( z) is any particular
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2,463 3 21 29. Add a comment. 0. Set z = y ′ and so z ″ + z = 0 whose general solution is z ( t) = A cos t + B sin t. One has that y is an antidervative of z so z ( t) = A sin t − B cos t + C and now we
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Homogeneous Linear Third Order Differential Equation y''' - 9y'' + 15y' + 25y = 0.
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