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Calculus Find the Absolute Max and Min over the Interval f (x)=12+4x-x^2 , [0,5] f (x) = 12 + 4x − x2 f ( x) = 12 + 4 x - x 2 , [0,5] [ 0, 5] Find the critical points. Tap for more steps (2,16) ( 2, 16)
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Finding absolute extrema on a closed interval Extreme value theorem tells us that a continuous function must obtain absolute minimum and maximum values on a closed interval. These
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Find the absolute maximum and minimum values of the function over the indicated interval, and indicate the x-values at which they occur. f (x) = 9x - 4:1-4,2] The absolute maximum value isat-
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Calculus Find the Absolute Max and Min over the Interval f (x)=x^3-6x^2+9x+5 , [-1,6] f (x) = x3 − 6x2 + 9x + 5 f ( x) = x 3 - 6 x 2 + 9 x + 5 , [−1,6] [ - 1, 6] Find the critical points. Tap for more