Combinations Formula: C ( n, r) = n! ( r! ( n − r)!) For n ≥ r ≥ 0. The formula show us the number of ways a sample of “r” elements can be obtained from a larger set of “n” distinguishable objects where order does not matter and repetitions are
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There are 496 combinations without repetition. Here’s the formula: 32!/ (32-2)!*2! = 32*31/2! = 496. Thanks! We're glad this was helpful. Thank you for your feedback. As a small
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